Demonstration 1 of 4
Beta sets the hurdle rate
How much return must a project offer, given how strongly it moves with the market?
CAPM prices only the market risk an asset adds to a diversified portfolio. The required return rises along a straight line in beta, and the slope is the market premium.
Scroll sideways for the whole equation
R_f = 2.5% is the risk-free return, E[R_M] the expected market return and beta the project's market exposure. The book's expansion has beta 1.3, and 0.8 after the redesign.
Predict first. If a prototype failure risk that is independent of the market is added, does the project's dot move?
Choose an example
Scroll sideways for the whole figure
Constructed example: the chapter's hypothetical expansion (risk-free 2.5%, market 8.5%, betas 1.3 and 0.8); betas 0.5 and 1.8 and market returns of 6.5% and 10.5% are added.
Calculated values
- Market premium
- 6.0%
- Required return
- 10.3%
- Benchmark at beta 0.8
- 7.3%
- Change versus beta 0.8
- +3.0 points
The market premium is 8.5 - 2.5 = 6.0%. CAPM gives 2.5 + 1.3 x 6.0 = 2.5 + 7.80 = 10.30%. Against the beta 0.8 benchmark of 7.30% the hurdle is 3.00 points higher.
Worked steps
- Premium = 8.5 - 2.5 = 6.0
- E[R] = 2.5 + 1.3 x 6.0 = 2.5 + 7.80 = 10.30%
- Benchmark = 2.5 + 0.8 x 6.0 = 7.30%
- Change = 10.30 - 7.30 = +3.00 points
Use the idea
Use a project beta, not the company beta, when the project's cyclicality differs, and show how the hurdle moves with beta and the premium.
Where the conclusion applies
Frictionless trading, common beliefs, a risk-free asset and a market proxy. Several priced factors, a stale beta or a poor market proxy would change the benchmark.
Check your understanding: With beta 0.8 and a market return of 10.5%, what is the hurdle rate?
Chapter 43 source: section "Capital asset pricing model".
Demonstration 2 of 4
One look or two: myopic loss aversion
Does the same investment feel worse when it is evaluated every period?
Aggregating lets a gain cancel a loss before the loss weight applies, so fewer outcomes are coded as losses. With lambda = 1 the framing does not matter.
Scroll sideways for the whole equation
Each period gains 15 points or loses 10 with probability one half. Losses are weighted by lambda (2 in the book). Two independent periods, with compounding ignored.
Predict first. At lambda = 1.5, is the aggregated value positive?
Choose an example
Scroll sideways for the whole figure
Constructed example: the chapter's hypothetical position (gain 15, loss 10, lambda 2); lambda values 1, 1.5 and 2.5 are added.
Calculated values
- Value per look
- -2.50
- Two separate looks
- -5.00
- Two periods aggregated
- 0.00
- Framing that feels better
- aggregated
Separate: 0.5(15) + 0.5[2.0(-10)] = 7.5 - 10.00 = -2.50 per look, -5.00 over two looks. Aggregated: 0.25(30) + 0.50(5) + 0.25[2.0(-20)] = 7.5 + 2.5 - 10.00 = 0.00. The aggregated framing feels better by 5.00 points. The payoffs are identical; only the evaluation boundary changed.
Worked steps
- Per look = 7.5 - 0.5 x 2.0 x 10 = -2.50
- Two looks = 2 x -2.50 = -5.00
- Aggregated = 7.5 + 2.5 - 0.25 x 2.0 x 20 = 0.00
Use the idea
Evaluate a long-horizon portfolio at the horizon that matters, unless you truly must sell after one period.
Where the conclusion applies
A piecewise linear value function, independent periods and no compounding. A real liquidity need after one period makes the separate view the right one.
Check your understanding: At lambda = 2.5, what are the separate and aggregated values?
Chapter 43 source: section "Myopic loss aversion".
Demonstration 3 of 4
Home bias and portfolio volatility
How much volatility does a household add by keeping most of its equity at home?
Mixing two imperfectly correlated markets lowers volatility. With equal expected returns, moving toward the capitalization weight cuts risk at no cost in return.
Scroll sideways for the whole equation
w is the domestic weight. Domestic volatility is 22%, foreign 16%, and the book's correlation is 0.30. The country is 10% of world equity; the household holds 75% of 200,000 dollars at home.
Predict first. Does lowering the correlation to 0 widen or narrow the volatility gap between w = 0.75 and w = 0.10?
Choose an example
Scroll sideways for the whole figure
Constructed example: the chapter's hypothetical household (volatilities 22% and 16%, correlation 0.30, weights 0.75 and 0.10); weights 0.40 and 1.00 and correlations 0 and 0.60 are added.
Calculated values
- Portfolio variance
- 0.032785
- Volatility
- 18.11%
- Volatility at world weight
- 15.21%
- Gap versus world weight
- 2.90 points
- Domestic dollars
- $150,000
Variance = 0.75^2(0.0484) + 0.25^2(0.0256) + 2(0.75)(0.25)(0.30)(0.0352) = 0.027225 + 0.0016 + 0.00396 = 0.032785. Volatility is 18.11% against 15.21% at the world weight, a gap of 18.11 - 15.21 = 2.90 points with the same expected return.
Worked steps
- w^2 x 0.22^2 = 0.75^2 x 0.0484 = 0.027225
- (1 - w)^2 x 0.16^2 = 0.25^2 x 0.0256 = 0.0016
- 2w(1 - w)(rho)(0.22)(0.16) = 0.00396
- Variance = 0.032785, volatility = sqrt(0.032785) = 18.11%
- Domestic dollars = 0.75 x 200,000 = $150,000
Use the idea
Measure home bias against world weights, then ask whether costs, taxes or domestic liabilities justify the remaining gap.
Where the conclusion applies
Equal expected net returns, fixed volatilities and correlation. Foreign-investment costs or liabilities tied to domestic shares can justify a larger home weight.
Check your understanding: At w = 1.00 and correlation 0.30, what is volatility?
Chapter 43 source: section "Home-bias puzzle".
Demonstration 4 of 4
Pooling shrinks risk, correlation brings it back
How much does pooling more stores reduce the risk of the average loss?
Independent losses average out at the rate of one over the square root of the pool size. A common component does not, and sets a floor under the risk.
Scroll sideways for the whole equation
Each store has a 4% chance of a 5,000-dollar loss. n stores pool their losses, and rho is the common pairwise loss correlation (0 or 0.10 in the book).
Predict first. At correlation 0.10, does going from 225 to 900 stores cut the SD in half?
Choose an example
Scroll sideways for the whole figure
Constructed example: the chapter's hypothetical bookstores (225 stores, 4%, 5,000 dollars, correlation 0 and 0.10); pools of 25, 100 and 900 and correlation 0.05 are added.
Calculated values
- Expected loss per store
- $200
- Individual SD
- $979.80
- Average-loss SD
- $65.32
- Floor as the pool grows
- $0.00
- Illustrative premium
- $240
Expected loss is 0.04(5,000) = 200 and individual variance 0.04(0.96)(5,000)^2 = 960,000, an SD of 979.80. Average-loss variance is 960,000(0.00 + 1.00/225) = 4,266.67, so the SD is 65.32 dollars. Independent losses shrink it by sqrt(225) = 15.00. The premium of 240 is 200 of expected claims plus 25 + 15 for administration and capital.
Worked steps
- Expected loss = 0.04 x 5,000 = 200
- Individual variance = 0.04 x 0.96 x 5,000^2 = 960,000
- Average variance = 960,000 x (0.00 + 1.00/225) = 4,266.67
- Average SD = sqrt(4,266.67) = 65.32
- Premium = 200 + 25 + 15 = 240
Use the idea
Before relying on a large pool, ask what share of its losses come from a shared cause.
Where the conclusion applies
Identical stores, equal pairwise correlation and a single loss size. Catastrophes or contagion make the correlation larger in bad years.
Check your understanding: With 100 independent stores, what is the average-loss SD?
Chapter 43 source: section "Risk Pooling, Insurance, and Diversification".