Math Class Didn’t Show Its Work, companion reader · Chapter 5

How Big Is It?

Read size from place first, then state what an estimate changed before you check it exactly.

These four demonstrations use the chapter's own numbers: two numerals that look alike, an expression whose grouping changes the question, the example theater, and the tile display. Predict first, change one choice, then check the picture against a calculation small enough to do by hand.

Every example in these readers is a constructed teaching example taken from or modeled on the book's own worked examples. The numbers are declared inputs chosen to make the mathematics visible. They are not measurements of any real person, product or study.

Demonstration 1 of 4

Compare from the left

Two numerals use almost the same digits. Which place decides which one is larger?

The chart lines the digits up under the same place labels. Reading from the top, the first row with different digits settles the comparison, because one unit in that place is worth more than every lower place put together.

\[5{,}084{,}000 = 10 \times 508{,}400\]

Each row is a base-ten place, from millions down to ones. A digit's value depends on its row: one row up means ten times as much. A 0 written in a row holds the other digits in their places.

Predict first. Before you switch to 640,090 and 604,900, guess which row will be outlined as the first place where the digits differ.

Choose an example

Figure: Compare from the left. Beside the chart, two bars on one shared scale show 5,084,000 and 508,400. A place-value chart with rows from millions to ones. The left column holds the digits of 5,084,000 and the right column the digits of 508,400. The millions row is outlined as the first place where the digits differ.
Which two numerals?: 5,084,000 and 508,400
Constructed example: the chapter's pair 5,084,000 and 508,400, its 58,400 with the internal zero removed, and its practice pair 640,090 and 604,900.

Calculated values

First numeral
5,084,000
Second numeral
508,400
First unequal place
millions (5 against 0)
Larger
5,084,000
Exactly ten times the second?
yes: 10 x 508,400 = 5,084,000

Reading from the left, the first unequal row is the millions row, where 5 is more than 0, so 5,084,000 is larger. The subtraction agrees: 5,084,000 - 508,400 = 4,575,600. Every digit also sits one place to the left of its partner, so 10 x 508,400 = 5,084,000 exactly.

Use the idea

When two long numbers look alike, line them up by place before you subtract anything. The first difference from the left tells you which is larger.

Where the conclusion applies

Whole numbers written in base ten and aligned by place. The rule fails if the numerals are lined up by their first digit instead of by place, or if two measurements carry different units.

Check your understanding: Which is larger, 3,402,000 or 3,420,000, and which place decides it?
Both have 3 millions and 4 hundred-thousands. In the ten-thousands place, 2 beats 0, so 3,420,000 is larger: 3,420,000 - 3,402,000 = 18,000.

Chapter 5 source: section "Place determines value". Demonstration C05-D01.

Demonstration 2 of 4

A grouping changes the question

Why do 6 + 4 x 3 and (6 + 4) x 3 give different answers?

Without parentheses, only the 4 is repeated: six items, then three groups of four. With parentheses, the whole sum of ten is repeated three times. Same numbers, different instructions.

\[6+4\times3\]

\[(6+4)\times3\]

The x means multiply. Parentheses mark a group to calculate first. Without them, multiplication is done before addition. Each small square in the picture is one item.

Predict first. With the parentheses added, how many rows of ten will the picture show?

Choose an example

Figure: A grouping changes the question. Rows of small squares, one row per group: six plus 3 groups of four. The squares total 18.
Grouping: 6 + 4 x n, Repeat count n: 3
Constructed example: the chapter's worked example 6 + 4 x 3, with one other repeat count.

Calculated values

Reading
six plus 3 groups of four
Rows drawn
4
Total
18
The other grouping gives
30

6 + 4 x 3 = 6 + 12 = 18. The expression is read as six plus 3 groups of four. Multiplication comes before addition unless parentheses group the sum first; the other grouping gives 30, a different question with a different answer.

Use the idea

Before calculating a line with several operations, say aloud what each grouping means. The words tell you which part is repeated.

Where the conclusion applies

Ordinary order of operations: groups first, then multiplication, then addition. No exponents appear here. Reading the line strictly left to right would give (6 + 4) x 3 even without parentheses, which is a different instruction.

Check your understanding: What are 50 - 6 x 7 and (50 - 6) x 7?
50 - 6 x 7 = 50 - 42 = 8, while (50 - 6) x 7 = 44 x 7 = 308.

Chapter 5 source: section "Read grouped arithmetic before calculating it". Demonstration C05-D02.

Demonstration 3 of 4

The example theater

Rounding 18 rows of 28 seats up to 20 rows of 30 gives 600. How far off is it, and which way?

Rounding a positive factor up makes the rectangle bigger, so the product grows. The hatched band shows exactly which seats the rounded model added.

\[18 × (30 - 2) = 504\]

Rows and seats per row are the two factors; their product counts seats. The teal rectangle is the supplied plan. The hatched rectangle is a rounded model.

Predict first. If only the seats per row are rounded, from 28 up to 30, will the estimate still be high?

Choose an example

Figure: The example theater. A teal rectangle of 18 rows by 28 seats, labeled 504 seats, inside a larger hatched rectangle of 20 rows by 30 seats labeled 600.
Rounded model: 20 rows x 30 seats
Constructed example: the chapter's example theater of 18 rows with 28 seats per row.

Calculated values

Rounded rows x seats per row
20 x 30
Estimate (seats)
600
Exact count (seats)
504
Estimate minus exact
96
Predicted direction
high

Rounded model: 20 x 30 = 600 seats. Exact count by compensation: 18 x 30 = 540, then 540 - 18 x 2 = 540 - 36 = 504 seats. 600 - 504 = 96. Every rounded factor moved up or stayed, so the estimate was predicted high, and it is 96 seats high. The hatched band is the seats the rounded model added.

Use the idea

When you estimate a total, write the rounded factors and their direction beside the result, so anyone can see why the estimate is high or low.

Where the conclusion applies

Every row has the same number of seats and both factors are positive. If one factor moved up and the other down, the direction would no longer be predictable from the rounding alone.

Check your understanding: A room has 17 rows of 26 chairs. Rounding to 20 x 30, is the estimate high or low, and by how much?
20 x 30 = 600 chairs, predicted high because both factors went up. Exact: 17 x (30 - 4) = 510 - 68 = 442, so 600 - 442 = 158 chairs high.

Chapter 5 source: section "An example theater". Demonstration C05-D03.

Demonstration 4 of 4

Which way does the estimate miss?

The tile display has 13 rows of 19. When can you tell, before multiplying, whether an estimate is high or low?

If every move is up or kept, the product can only grow. If every move is down or kept, it can only shrink. One up and one down can pull either way, so only the exact count settles it.

\[13 × 19 = 13 × (20 - 1)\]

Each rounded factor moves up, moves down, or is kept. The gold bar is the estimate; the teal bar is the exact count of 247 tiles.

Predict first. Using 15 rows and 20 tiles per row, will the estimate land above 247 or below it?

Choose an example

Figure: Which way does the estimate miss?. The exact 13 by 19 tile rectangle with a dashed 10 by 20 rounded rectangle over it. 10 tiles are hatched as added by rounding and 57 as missed.
Rounded rows: 10, Rounded tiles per row: 20
Constructed example: the chapter's tile display of 13 rows with 19 tiles per row and its two rounding routes.

Calculated values

Rounded rows
10 (down)
Rounded tiles per row
20 (up)
Estimate (tiles)
200
Exact count (tiles)
247
Predicted before multiplying
not settled by the arrows
Actual
low by 47

Estimate: 10 x 20 = 200 tiles. Exact: 13 x (20 - 1) = 260 - 13 = 247 tiles. 247 - 200 = 47, so the estimate is 47 tiles low. One factor moved down and one moved up, so the arrows alone could not predict the direction.

Use the idea

Mark an arrow beside each rounded factor. If the arrows agree, say high or low before you multiply exactly; if they disagree, say the direction is not settled.

Where the conclusion applies

Two positive factors and a stated rounding for each. The rule says nothing about how large the miss is, and it fails for mixed directions.

Check your understanding: Estimate 42 boxes of 47 cards as 40 x 50. Can you predict the direction, and what is the miss?
No: 42 went down and 47 went up. 40 x 50 = 2,000 and 42 x (50 - 3) = 2,100 - 126 = 1,974, so the estimate is 26 cards high.

Chapter 5 source: section "Worked example: a tile display". Demonstration C05-D04.