Demonstration 1 of 4
Sorting pays only with complementarity
When does pairing the best technician with the best plant raise total output?
Sorting gains only when skill and quality are complements (increasing differences). With an additive technology the pairing is irrelevant, and with a negative interaction crossing wins.
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s is technician skill (s_H set here, s_L = 1), q plant quality (q_H = 3, q_L = 2) and F(s, q) match output. Sorted pairs high with high; crossed pairs high with low.
Predict first. Under F = s + q, does sorting change total output?
Choose an example
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Constructed example: the chapter's hypothetical values are s_H = 4, s_L = 1, q_H = 3, q_L = 2 and the three technologies; s_H = 2 and 3 are added.
Calculated values
- Sorted output
- 14.0
- Crossed output
- 11.0
- Sorting gain
- 3.0
Hypothetical market from the chapter, technology F = sq. Sorted output is 4(3) + 1(2) = 14.0 and crossed output 4(2) + 1(3) = 11.0, so sorting adds 3.0 units.
Worked steps
- Sorted: 4(3) + 1(2) = 14.0
- Crossed: 4(2) + 1(3) = 11.0
- Gain = 14.0 - 11.0 = 3.0: sorting adds 3.0 units
Use the idea
Before reading a wage and firm-quality correlation as productive sorting, ask whether the inputs are complements in output.
Where the conclusion applies
Two types on each side, known types and flexible transfers that support the efficient assignment.
Check your understanding: With F = sq and s_H = 2, what is the sorting gain?
Chapter 85 source: section "Assortative matching".
Demonstration 2 of 4
Matching function, finding rates, steady unemployment
How do matching efficiency and vacancies set job-finding, vacancy-filling and steady unemployment?
More vacancies per searcher help workers find jobs but congest the firm side. Higher matching efficiency raises both rates and lowers steady unemployment.
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M is monthly matches, A matching efficiency, U = 800 unemployed and V vacancies; f = M/U, q = M/V, theta = V/U, and s = 0.03 the separation rate.
Predict first. Raising vacancies from 450 to 800: does each vacancy fill faster or slower?
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Constructed example: the chapter's hypothetical values are U = 800, V = 450 and 800, A = 0.6 and 0.4 and s = 0.03; A = 0.7 and V = 600 are added.
Calculated values
- Matches M
- 360.0
- Job-finding rate f
- 0.450
- Vacancy-filling rate q
- 0.800
- Tightness theta
- 0.5625
- Steady unemployment u*
- 6.25%
Hypothetical labor force of 10,000 with 800 unemployed. Efficiency 0.6 and 450 vacancies give 360.0 matches, so f = 360.0 / 800 = 0.450 and q = 0.800. With separations at 0.03, steady unemployment is 0.03 / (0.03 + 0.450) = 6.25%.
Worked steps
- M = 0.6 sqrt(800 x 450) = 0.6 x 600.00 = 360.0
- f = 360.0 / 800 = 0.450; q = 360.0 / 450 = 0.800
- theta = 450 / 800 = 0.5625
- u* = 0.03 / (0.03 + 0.450) = 0.0625, or 6.25%
Use the idea
Separate a fall in job finding caused by fewer vacancies from one caused by worse matching efficiency; they call for different responses.
Where the conclusion applies
Constant-returns matching with alpha = 0.5, stocks held at the comparison date, and a steady state that is an accounting benchmark rather than a forecast.
Check your understanding: With A = 0.6 and V = 600, what are f and u*?
Chapter 85 source: section "Search-and-matching unemployment".
Demonstration 3 of 4
Moving along versus shifting the Beveridge curve
How many vacancies sustain steady flows at each unemployment level, and what does worse matching do?
Fewer unemployed need more vacancies to generate the same hiring flow, so the curve slopes down. Lower matching efficiency raises the vacancies needed at every U: the curve shifts out.
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L = 5,000 is the labor force, U unemployment, V vacancies, s = 0.04 the separation rate and M = A sqrt(UV) monthly hires. Steady flows need s(L - U) = M.
Predict first. Halving matching efficiency at U = 400: does required V double or quadruple?
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Constructed example: the chapter's hypothetical values are L = 5,000, s = 0.04, A = 0.8 and 0.4 and U = 500 and 400; U = 600 is added.
Calculated values
- Separations s(L - U)
- 180
- Required vacancies V
- 101.25
- Hires at V = 101.25
- 180.0
Hypothetical labor force of 5,000 with separation rate 0.04. At U = 500, separations are 0.04 x 4,500 = 180, so steady flows need V = (180 / 0.8)^2 / 500 = 101.25 vacancies. Changing U moves along a curve; changing A shifts it.
Worked steps
- Separations = 0.04 x (5,000 - 500) = 180
- V = (180 / 0.8)^2 / 500 = 225.0^2 / 500 = 101.25
- Check: 0.8 sqrt(500 x 101.25) = 180.0 hires
Use the idea
When vacancies and unemployment rise together, suspect a shift in matching efficiency rather than a demand movement along the curve.
Where the conclusion applies
Square-root matching and a fixed separation rate; the curve shows steady flows, not adjustment.
Check your understanding: At U = 600 and A = 0.8, what vacancy stock sustains steady flows?
Chapter 85 source: section "Beveridge curve".
Demonstration 4 of 4
Monopsony, wage floors, and mobility
How does a firm facing upward-sloping labor supply set pay, and what does a wage floor do?
Hiring one more worker raises pay for everyone, so the monopsonist stops short and pays below MRP. A floor between the monopsony wage and MRP removes that motive and raises both pay and jobs. A flatter supply curve (more mobility) also raises employment.
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w = 8 + bL is the inverse labor supply facing the firm, ME = 8 + 2bL marginal expenditure and MRP = 20 each worker's marginal revenue product. A floor fixes the wage the firm must pay.
Predict first. Does a floor of 16 raise or reduce employment relative to monopsony (slope 0.5)?
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Constructed example: the chapter's hypothetical values are intercept 8, slopes 0.5 and 0.25, MRP 20 and a floor of 16; slope 1.0 and a floor of 18 are added.
Calculated values
- Employment L
- 12
- Wage w
- 14
- Markdown MRP - w
- 6
- Competitive employment
- 24
Hypothetical workshop from the chapter with supply w = 8 + 0.50L and MRP 20. Setting ME = 8 + 1.0L equal to 20 gives L = 12 / 1.0 = 12 and w = 8 + 0.50 x 12 = 14. The competitive benchmark is L = 24.
Worked steps
- ME = 8 + 1.0L = 20, so L = 12 / 1.0 = 12
- w = 8 + 0.50 x 12 = 14
- Markdown = 20 - 14 = 6; competitive L = 12 / 0.50 = 24
Use the idea
Judge a wage floor against the employer's markdown and the competitive benchmark, not as always good or always bad for jobs.
Where the conclusion applies
Linear supply, constant MRP and a single common wage; a floor above 20 would end profitable hiring.
Check your understanding: With slope 0.5 and a floor of 18, what are L and w?
Chapter 85 source: section "Monopsony and Labor-Market Power".